Question

A sample of gas at an initial volume of 4.2 L an initial pressure of 1.12 atm, and an initial temperature of 186 K simultaneously changes its temperature to 355 K and its pressure to 0.82 atm What is the final volume of the gas? [3 SF) (10.91)

Answer 1

To solve this problem, we can use the combined gas law, which states:

(P1 * V1) / T1 = (P2 * V2) / T2

Where P1, V1, and T1 represent the initial pressure, volume, and temperature, and P2, V2, and T2 represent the final pressure, volume, and temperature.

Substituting the given values into the equation, we have:

(1.12 atm * 4.2 L) / 186 K = (0.82 atm * V2) / 355 K

Simplifying the equation:

4.704 atm*L/K = (0.82 atm * V2) / 355 K

Cross-multiplying:

4.704 atmLK = 0.82 atm * V2

Dividing both sides by 0.82 atm:

5.739 atmLK / atm = V2

Simplifying:

V2 = 5.739 L

Therefore, the final volume of the gas is 5.739 L (rounded to three significant figures).