Answer:
[tex]P=40 \ W[/tex]
Conceptual:
[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Equations for Work:}}\\W=F \Delta rcos(\theta) \ \text{(Constant} \ \vec F) \\W= \int\limits^{r_2}_{r_1} {Fcos(\theta)} \, dr \ \text{(Varible} \ \vec F) \end{array}\right }[/tex]
The angle "θ" is the angle between the force applied and the direction of displacement.
[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Formula for Power:}}\\\\P=\frac{W}{t} \end{array}\right}[/tex]
Explanation:
Given that an engine does 400 J of work in 10 seconds. Find the power of the engine.
[tex]W=400 \ J\\t=10 \ s[/tex]
Plug these values into the formula for power.
[tex]P=\frac{W}{t} \\\\\Longrightarrow P=\frac{400}{10}\\\\\therefore \boxed{P=40 \ W}[/tex]
Thus, the engines power is calculated.