Answer:
Step-by-step explanation:
You want two numbers such that the larger is 2 less than 5 times the smaller, and their sum is 22 after it has been increased by 6.
Let x represent the smaller number. Then the larger is (5x-2) and the relation with regard to the sum is ...
(x) +(5x -2) +6 = 22
6x = 18 . . . . . . . . . . . . subtract 4 and simplify
x = 3 . . . . . . . . . divide by 6
(5x -2) = 5·3 -2 = 13
The two numbers are 3 and 13.
Check
The sum of the two numbers is 3+13 = 16. When that is increased by 6, the result is 16+6 = 22, as required.
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