Question

Two families went to see their students in the school play. The first family
paid 119 dollars for seven adult tickets and six student tickets. The
second family paid 79 dollars for four adult tickets and five student
tickets. How much was each adult ticket and each student ticket?

Answer 1

Answer:

• adult ticket: $11
• student ticket: $7

Step-by-step explanation:

You want the price of each kind of ticket when 7 adult and 6 student tickets sold for $119, and 4 adult and 5 student tickets sold for $79.

Setup

The two sales can be represented by the equations ...

  7a +6s -119 = 0

  4s +5s -79 = 0

Solution

We can solve these equations using the "cross multiplication method" as follows:

  D = (7)(5) -(4)(6) = 11

  Da = (6)(-79) -(5)(-119) = 121

  Ds = (-119)(4) -(-79)(7) = 77

a = Da/D = 121/11 = 11

s = Ds/D = 77/11 = 7

Each adult ticket was $11, and each student ticket was $7.

You can read more about the cross multiplication method here:

https://brainly.com/question/26397343

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