Question

How many moles of helium would occupy a volume of 1.255 L at a pressure of 1.47 atm at a temperature of 21℃?

Answer 1

Answer:

$\huge\boxed{\sf n \approx 0.076\ moles}$

Explanation:

Given data:

Volume = V = 1.255 L

Pressure = P = 1.47 atm

Temperature = T = 21 + 273 = 294 L

R = 0.08206 L atm/mol K

Required:

No. of moles = n = ?

Formula:

• PV = nRT

Solution:

Put the given data in the above formula.

(1.47)(1.255) = n(0.08206)(294)

1.844 = n (24.13)

• Divide both sides by 24.13

1.844 / 24.13 = n

0.076 moles ≈ n

n ≈ 0.076 moles

$\rule[225]{225}{2}$