The half life of a certain substance is about 4 hours. The graph shows the decay of a 50 gram sample of the substance that is measured every hour for 9 hours.

Which function can be used to determine the approximate number of grams of the sample remaining after t hours?

a
y = 50(0.85)x

b
y = 25(0.15)x

c
y = 50(0.15)x

d
y = 25(0.85)x

The half life of a certain substance is about 4 hours The graph shows the decay of a 50 gram sample of the substance that is measured every hour for 9 hours Whi class=

Respuesta :

I can't see how any of those formulas show exponential decay.  (Did you type those correctly?)

The formula that will show the remaining amount correctly is:
ending amount = Bgng Amount / 2^n
where "n" is the number of haf-lives.

So, for example if half life = 4 hours and if we want to calculate the amount after 9 hours (that's 2.25 half-lives) then:
ending amount = Bgng Amount / 2^n
ending amount = 50 / (2^(9/4))
ending amount = 50 / 2^2.25
ending amount = 50 / 4.75682846
ending amount = 10.5112 grams
Looking at the graph, we see that's about right.
 

Ver imagen wolf1728

Answer:

a) [tex]y = 50(0.85)^x[/tex]

Step-by-step explanation:

Let the function that shows the given situation is,

[tex]y=ab^x[/tex]

Where a and b are any unknown numbers,

By the given diagram,

When x = 1, y = 42.5,

[tex]\implies 42.5 = ab^1[/tex]

[tex]\implies ab = 42.5[/tex] ------(1)

Again, when x = 4, y = 26,

[tex]\implies 26 = ab^4[/tex]

[tex]\implies 26 = ab(b^3)[/tex]  

[tex]\implies 26 = 42.5(b^3)[/tex]    ( By equation (1) )

[tex]\implies 0.611764706 = b^3[/tex]

[tex]\implies 0.84890965425 = b[/tex]

Again, By equation (1),

a = 50.0642203646

Hence, the equation that shows the given graph,

[tex]y = 50.0642203646(0.84890965425)^x[/tex]

[tex]\implies y = 50(0.85)^x[/tex]

Option a is correct.

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