Respuesta :

Total mass of the Sun = 2x10^30kg 

So 76% of that = (2x10^30kg)*(0.76) = 1.52x10^30kg ----> total amount of Hydrogen if only 12% of that is used for fusion, then (1.52x10^30kg)*(0.12) = 1.82x10^9kg

The total mass of hydrogen available for fusion over the lifetime of the sun is mathematically given as

Ms= 1.82x10^9kg

What is the total mass of hydrogen available for fusion?

Question Parameters:

76% of the suns mass  = (2x10^30kg)*(0.76)

76% of the suns mass  = 1.52x10^30kg

Generally, when total amount of Hydrogen is at 12% used for fusion

Therefore

Ms=(1.52x10^30kg)*(0.12)

Ms= 1.82x10^9kg

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