Respuesta :
Total mass of the Sun = 2x10^30kg
So 76% of that = (2x10^30kg)*(0.76) = 1.52x10^30kg ----> total amount of Hydrogen if only 12% of that is used for fusion, then (1.52x10^30kg)*(0.12) = 1.82x10^9kg
So 76% of that = (2x10^30kg)*(0.76) = 1.52x10^30kg ----> total amount of Hydrogen if only 12% of that is used for fusion, then (1.52x10^30kg)*(0.12) = 1.82x10^9kg
The total mass of hydrogen available for fusion over the lifetime of the sun is mathematically given as
Ms= 1.82x10^9kg
What is the total mass of hydrogen available for fusion?
Question Parameters:
76% of the suns mass = (2x10^30kg)*(0.76)
76% of the suns mass = 1.52x10^30kg
Generally, when total amount of Hydrogen is at 12% used for fusion
Therefore
Ms=(1.52x10^30kg)*(0.12)
Ms= 1.82x10^9kg
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