Question

On january 22nd, 2006, kobe bryant scored 81 points against the toronto raptors. including three-pointers, two-pointers, and free- throws he made 46 shots. he made three times as many two-point shots as three-point shots. how many free-throws did kobe bryant make?

Answer 1

x = 3 pointers, y = 2 pointers, z = free throws

x + y + z = 46
3x + 2y + z = 81
y = 3x

x + 3x + z = 46
4x + z = 46
z = 46 - 4x

3x + 2y + z = 81
3x + 2(3x) + 46 - 4x = 81
3x + 6x + 46 - 4x = 81
5x + 46 = 81
5x = 81 - 46
5x = 35
x = 35/5
x = 7......he made 7 three pointers

y = 3x
y = 3(7)
y = 21....he made 21 two pointers

z = 46 - 4x
z = 46 - 4(7)
z = 46 - 28
z = 18.....he made 18 free throws <====

Answer 2

Answer:

ok

Step-by-step explanation: