Question

If f(x) = 3x 1 and f^-1 = x-1/3 , then the ordered pair of f^-1(10) =

Answer 1

f(x)=3x+1
f⁻¹(x)=$\frac{x-1}{3}$

f⁻¹(10)=
just subsitute 10 for x in that equaiton
f⁻¹(10)=$\frac{10-1}{3}$
f⁻¹(10)=$\frac{9}{3}$
f⁻¹(10)=3

orderd pari is (10,3)