Respuesta :

2th
The probability would be 25% for a homozygous dominant offspring.

Answer:

The probability of a homozygous dominant (BB) offspring resulting from a cross between two parents with the genotype Bb is [tex]25\\[/tex]%

Explanation:

Given -

Two parents which are crossed with each other has genotype - Bb

One of their offspring has genotype BB, and this is homozygous dominant

which means B is dominant and b is recessive allele.

Lets see the punnet square of cross between the two parents with genotype "Bb"

B b

B BB Bb

b Bb bb

Four offsprings are produced out of which only one is homozygous dominant "BB"

Thus , the probability of a homozygous dominant (BB) offspring resulting from a cross between two parents with the genotype Bb is

[tex]\frac{1}{4} *100\\= 25%\\[/tex]%