Question

A car weighing 15,000 N is on a hydraulic lift platform measuring 10 m2
. What is the area of the smaller piston if a force of 1,100 N is used to lift the car?

Answer 1

PRESSURE = FORCE/AREA

F1/A1=F2/A2
15,000/10=1,100/A2
A2=1,100/1500=11/15
It is approximately 0.733m^2 

Answer 2

The area of the smaller piston is about 0,733 m2

To measure the pressure in a surface, it is necessary to relate the value of the applied force and the size of the area that suffers this force, in such a way that:

                                                  $p = \frac{F}{A}$

As in a hydraulic platform, the pressure is equal on both sides, the initial pressure must be equal to the final pressure:

                                                    $\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$

Applying the values ​​given in the question we have:

                                          $\frac{15,000}{10} = \frac{1,100}{A_{2}}$

                                             $A_{2}=\frac{1,100}{1,500}$

                                             ${A_{2} = 0,73m^{2}$

So, the area of the smaller piston if a force of 1,100 N is equal to 0,73m2

Learn more about hydraulic systems in: brainly.com/question/18328907