Question

A 12- sided number cube with the numbers 1 through 12 is rolled.

Rounded to the nearest humdreth, the probability that the number cube lands on a number greater than 10 is

Answer 1

I think it would be 2/12=1/6 or 0.17

Answer 2

Answer:

Probability is 0.17.

Step-by-step explanation:

Given : A 12- sided number cube with the numbers 1 through 12 is rolled.

To find : The probability that the number cube lands on a number greater than 10 ?

Solution :

$\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}$

A 12- sided number cube with the numbers 1 through 12 is rolled.

Total number of outcomes = 12

Number cube lands on a number greater than 10

Favorable outcomes(11 and 12)=2

$\text{P(no. greater than 10)}=\frac{2}{12}$

$\text{P(no. greater than 10)}=\frac{1}{6}$

$\text{P(no. greater than 10)}=0.1666$

Nearest to hundredth, Probability is 0.17.