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Hank started a savings account in June of 2002. On June 2006, he had $3,800. On June 2014, he had $8,600. If Hank's saving is modeled by a linear function, what was his initial deposit?

Respuesta :

Answer: $1,400

Step-by-step explanation:

slope =  

8,600 - 3,800

2014 - 2006

= 600

y = mx + b

3,800 = 600(2006) + b

b = -1,199,800

thus,

y = mx + b

y = 600x - 1,199,800

y = 600(2002) - 1,199,800

y = 1,400

Answer:

the answer is c

Step-by-step explanation:

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