Question

if the thermal energy of a system increases by 400 j , and 1100 j of heat was added to the system how much work did the system do?

Answer 1

The equation used here is ΔU=Q-W,
where, ΔU is the change in the system's internal energy, Q is the energy transferred to or from the system by  heat, and W is the energy transferred to or from the system by work.
 
Known:
ΔU=400J
Q=1100 J
W=?

Plug into the equation:
400=1100-W
Therefore W=700 J.

So the system did 700 J of work.

Answer 2

Work is done by an object when energy is transferred. The work done by the system is 700 J.

What is work done by an object?

The work can be defined as the energy transferred to or from an object by applying the force along with a displacement.

Given that the change in the energy of the system is 400 J and 1100 J of heat was added to the system.

In this case, the work done by the system is calculated using the formula given below.

$U = Q -W$

Where U is the change in the system's internal energy which is 400 J, Q is the amount of heat added to the system which is 1100 J and W is the total work done by the system.

$400=1100-W$

$W = 1100 -400$

$W = 700 \;\rm J$

Hence we can conclude that the work done by the system is 700 J.

To know more about the work done, follow the link given below.

https://brainly.com/question/3902440.