Answer: Volume occupied by oxygen gas at STP is 16.78 liters.
Explanation:
At STP, value of pressure ,P = 1atm
At STP, value of Temperature ,T = 273 K
Number moles of oxygen gas ,n= 0.75 moles
According to ideal gas equation :
PV=nRT, R = Universal Gas constant = 0.0820 L atm/mol K
[tex]1 atm\times V=0.75 mol\times 0.0820 L atm/mol K\times 273 K[/tex]
[tex]V=\frac{0.75 mol\times 0.0820 L atm/mol K\times 273 K}{1 atm}=16.78 L[/tex]
Volume occupied by oxygen gas at STP is 16.78 liters.
