Question

The sum of three consecutive numbers is 84. what is the smallest of the three numbers?

Answer 1

$a,a+1,a+2-\ three\ consecutive\ numbers\\\\ a+a+1+a+2=84\\\\ 3a+3=84\ \ \ | subtract\ 3\\\\ 3a=81\ \ \ \ | divide\ by\ 3\\\\ a=27\\\\ The\ smallest\ is\ 27.$

Answer 2

x= first number x+1=second number x+2 = third number add and equal to 84 3x+3=84 3x= 81 x=27 x+1=28 x+2=29