Question

At 189k a sample of gas has a volume of 32.0 cm3. What volume does the gas occupy at 242 k

Answer 1

Data:
$V_{initial} = 32.0\:cm^3$
$T_{initial} = 189\:K$
$V_{final} = ?$
$T_{final} = 242\:K$

By the first Law of Charles and Gay-Lussac, we have: 
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 32.0 }{ 189\:K } = \frac{ V_{f} }{ 242 }$
Product of extremes equals product of means:
$189* V_{f} = 32.0*242$
$189 V_{f} = 7744$
$V_{f} = \frac{7744}{189}$
$V_{f} = 40.97354...\to \boxed{V_{f} \approx 41\:cm^3}$