Question

What is the length of the base of a right triangle with an area of 24 m² and a height of 4 m? 3 m 6 m 12 m 96 m

Answer 1

The area of a triangle is A = 1/2(b)(h)  All we have to do is to plug in what they give us and solve for the unknown.

24 = 1/2(b)(4)        combine like terms...1/2 and 4
24 = b2                  divide by 2
12 = base              this would be the legth of the base

Answer 2

Area of a triangle is decidable by its height and base length. The length of the base of the considered triangle is given by: Option C: 12 m

What is a right angled triangle?

A right angled triangle is a triangle having one of its angle with measure of 90°

The slant side of that triangle is called Hypotenuse and it is the longest side in that triangle.

Its vertical side is of length equal to its height (as height is vertical distance from base to top vertex of considered triangle)

What is the area of a triangle with base length b and height h?

Suppose that the considered triangle has got:

Base length = b units.

height = h units,

Then its area A is given as:

$A =- \dfrac{1}{2} \times b \times h \: \rm unit^2$

For the given case, let we assume that the triangle considered has its base of length 'b' meters

Then, as it is already given that its height is 4 meters and area is 24 m², thus,

$A = \dfrac{1}{2} \times b \times h\\\\24 = \dfrac{1}{2} \times b \times 4 = b \times 2\\\\\text{Dividing both the sides by 2}\\\\\dfrac{24}{2} = \dfrac{2 \times b}{2} = b\\\\12 = b\\b = 12 \: \rm meters$

Thus, the length of the base of the considered triangle is given by: Option C: 12 m

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