Answer:
Step-by-step explanation:
You want to know the consecutive integers that bound the values of 30^(1/5) and 45^(1/3).
The fifth root of 30 will lie between the two integers whose 5th powers lie on either side of 30:
1^5 = 1 < 30
2^5 = 32 > 30
So, the fifth root of 30 lies between 1 and 2:
[tex]\boxed{1 < \sqrt[5]{30} < 2}[/tex]
The cube root of 45 will lie between the two integers whose cubes lie on either side of 45:
3^3 = 27 < 45
4^3 = 64 > 45
So, the cube root of 45 lies between 3 and 4:
[tex]\boxed{3 < \sqrt[3]{45} < 4}[/tex]
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Additional comment
A calculator confirms this:
[tex]\sqrt[5]{30}\approx 1.974\\\sqrt[3]{45}\approx3.557[/tex]