karlajallday karlajallday 20-01-2023 Chemistry contestada 2K3N + 3CaCl2 → 6KCl + Ca3N2 1 mol K3N = 131.301 g K3N 1 mol CaCl2 = 110.984 g CaCl2 1 mol KCl = 74.551 g KCl 1 mol Ca3N2 = 148.248 g Ca3N2 How many grams of CaCl2 would it take to make 1.5 moles of KCl?
