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Doubtnut
Question
How many ways can 2 identical red chairs and 4 identical blue chairs be arranged in one row ?
Answer · 21 votes
There is a formula that applies to this situation. The number of distinct permutations of n things, a of which are indistinguishable, b of which are indistinguishable, atc., is `(n!)/(a!b!...)` Here there are 6 chairs, 2 of which are indistinguishable and 4 of which are indistinguishable, so the number of permutations is `(6!)/(2!4!)=(6.5.4.3.2.1)/(2.1.4.3.2.1)=(6.5)/(2)=15`
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Brainly.in
Question
18 blue chairs and 27 red chairs have to be arranged in rows in such a way that there are an equal no. of chairs of the same colour in each row, what is the maximum no. of chairs that can be arranged in each row and how many rows can the chairs be arranged in?
Answer · 27 votes
Answer: highest number of chairs in each row is 9Total rows is 5Step-by-step explanation:Find the Highest Common Factor of 18 and 27The HCF of 18, 27 is 9Thus the maximum no of chairs that can be arrranged in each row is 9Total rows is (18+27)/9 = 5Please brainlist my answer, if helpful!
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