Answer: F = (6C/5) + 32
To express F in terms of C, rearrange the equation to isolate 'F'.
Inverse Operations
To rearrange the equation, we want 'F' to be by itself. To move numbers to the other side, we do the other pair of inverse operation to both sides. This cancels out what we don't need while keeping the left and right sides equal.
Pairs of inverse operations
- Multiply ⇔ Divide
- Add ⇔ Subtract
Calculate
[tex]\displaystyle { C = \frac{5}{6}*(F-32) }[/tex] Start with the equation in the question.
[tex]\displaystyle { C = \frac{5*(F-32)}{6} }[/tex] Rewrite. This is the same as the question.
[tex]\displaystyle { 6C = \frac{5*(F-32)}{6}*6 }\\[/tex] Multiply both sides by 6.
[tex]\displaystyle { 6C = 5*(F-32) }[/tex] Cancelled out 6 on the right.
[tex]\\\displaystyle { \frac{6C}{5} = \frac{5*(F-32)}{5} }[/tex] Divide both sides by 5.
[tex]\displaystyle { \frac{6C}{5} = (F-32) }[/tex] Cancelled out 5 on the right.
[tex]\displaystyle { \frac{6C}{5} = F-32 }[/tex] We don't need the brackets if 'F - 32' is alone.
[tex]\displaystyle { \frac{6C}{5}+32 = F-32+32 }[/tex] Add 32 to both sides.
[tex]\displaystyle { \frac{6C}{5}+32 = F }[/tex] Cancelled out 32 on the right.
[tex]\displaystyle { F = \frac{6C}{5}+32 }[/tex] Keep lone variables on the left side.
Therefore, the equation to convert Celsius to Fahrenheit is:
[tex]\displaystyle { F = \frac{6C}{5}+32 }[/tex]
To learn about another problem on isolating variables, check out:
https://brainly.com/question/25141227
