$33534.73 should be deposited today to reach the goal assuming on other deposits.
Let the lump sum be P.
The interest, I, on a rate, R%, per annum after T years is given by
I = PRT/100
The amount, A, is
A = P + I = (1 + RT/100)
After 2 years at 4.5% interest rate, the amount is
A = P( 1 + 4.5 × 2 /100)
= 1.09P
$7500 is added after 2 years. The principal for the beginning of the third year is then
1.09P + 7500
The amount after the next 3 years is
A = ( 1.09P + 7500) (1 + 4.5 ×3/100)
= (1.09P + 7500) × 1.135
This is the amount expected to be saved.
5000 = (1.09P + 7500) × 1.135
Solving for P, we have
1.09P + 7500 = 44052.86
⇒ 1.09P = 36552.86
⇒ P = 33534.23
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