Question

Disregarding friction, how fast will the block move after the spring is released all the way and the block slides away from it? 3.5 m/s 4.1 m/s 13 m/s 16 m/s

Answer 1

Disregarding friction, how fast will the block move after the spring is released all the way and the block slides away from it is 3.5 m/s 4.1 m/s 13 m/s 16 m/s

$3.5 \cdot \frac{m}{s} \cdot 4.1 \cdot \frac{m}{s} \cdot 13 \cdot \frac{m}{s} \cdot 16 \cdot \frac{m}{s}=\frac{2984.8 m^4}{s^4}$

Steps

$3.5 \cdot \frac{m}{s} \cdot 4.1 \cdot \frac{m}{s} \cdot 13 \cdot \frac{m}{s} \cdot 16 \cdot \frac{m}{s}$

Multiply fractions: $\quad a \cdot \frac{b}{c} \cdot \frac{d}{e}=\frac{a \cdot b \cdot d}{c \cdot e} =3.5 \cdot 4.1 \cdot \frac{13 \cdot 16 \mathrm{mmmm}}{\mathrm{ssss}}$

Simplify $\frac{m m m m \cdot 13 \cdot 16}{s s s s}: \quad \frac{208 m^4}{s^4} =3.5 \cdot 4.1 \cdot \frac{208 m^4}{s^4}$

Multiply the numbers: $3.5-4.1=14.35$

$=14.35 \cdot \frac{208 m^4}{s^4}$

Multiply fractions:$\quad a \cdot \frac{b}{c}=\frac{a \cdot b}{c}$

$=\frac{208 m^4 \cdot 14.35}{s^4}$

Multiply the numbers: $208 \cdot 14.35=2984.8$

$=\frac{2984.8 m^4}{s^4}$

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