Question

From the edge of a cliff, a 0.55 kilogram projectile is launched with an initial kinetic energy of 1550 Joule. The projectile’s maximum upward displacement from the launch point is 145 meter. What is the horizontal components of its launch velocity?

Answer 1

The horizontal components of its launch velocity is 75.07m/s when a projectile is launched from the edge of a cliff.

Given mass of projectile (m) = 0.55kg

initial kinetic energy (KE1) = 1550J

displacement of projectile from launch pad (s) = 145m

The vertical component of velocity disappears at the point of maximum height, where y=140m, but the horizontal component stays the same as when the object was launched (if we neglect air friction).

Its kinetic energy at that moment is KE = 1/2mv^2

1550 = 1/2x0.55xv^2

v = 75.07m/s

Hence the horizontal components of its launch velocity = 75.07m/s

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