The speed of galaxy B from observer at galaxy A is [tex]$u_{\mathrm{x}, \mathrm{B}}^{\prime} & =0.6 c[/tex] and speed of galaxy C from observes at galaxy A is [tex]${data-answer}amp; u_{\mathrm{x}, \mathrm{C}}^{\prime}=0.88 c .[/tex]
A galaxy is an enormous collection of gas, dust, billions of stars, and their solar systems all locked together by gravity.
A galaxy is a massive cluster of stars and planets that spans many billions of light years. A far-off galaxy has been found by astronomers. the solar system, the nebula, and the star system Additional Galaxy Synonyms
We must locate our system K' in galaxy A if we are seeking for the speeds of galaxies B and C as seen by someone in galaxy A. Therefore, speed v is equal to v = -0.6 c.
Speed of galaxy B from observer at galaxy A is:
[tex]$u_{\mathrm{x}, \mathrm{B}}^{\prime} & =\frac{u_{\mathrm{x}, \mathrm{B}}-v}{1-\frac{v}{c^2} u_{\mathrm{x}, \mathrm{B}}} \\[/tex]
substitute the values in the above equation, we get
[tex]$u_{\mathrm{x}, \mathrm{B}}^{\prime} & =\frac{0-(-0.6 c)}{1-\frac{-0.6 c}{c^2} \cdot 0} \\[/tex]
simplifying the above equation, we get
[tex]$u_{\mathrm{x}, \mathrm{B}}^{\prime} & =0.6 c[/tex]
Speed of galaxy C from observes at galaxy A:
[tex]${data-answer}amp; u_{\mathrm{x}, \mathrm{C}}^{\prime}=\frac{u_{\mathrm{x}, \mathrm{C}}-v}{1-\frac{v}{c^2} u_{\mathrm{x}, \mathrm{C}}} \\[/tex]
substitute the values in the above equation, we get
[tex]${data-answer}amp; u_{\mathrm{x}, \mathrm{C}}^{\prime}=\frac{0.6 c-(-0.6 c)}{1-\frac{-0.6 c}{c^2} \cdot 0.6 c} \\[/tex]
simplifying the above equation, we get
[tex]${data-answer}amp; u_{\mathrm{x}, \mathrm{C}}^{\prime}=0.88 c .[/tex]
Therefore, the speed of galaxy B from observer at galaxy A is [tex]$u_{\mathrm{x}, \mathrm{B}}^{\prime} & =0.6 c[/tex] and speed of galaxy C from observes at galaxy A is [tex]${data-answer}amp; u_{\mathrm{x}, \mathrm{C}}^{\prime}=0.88 c .[/tex]
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