Respuesta :
He pitches at a 38 m/s pace.
If you would want a better understanding of the issue, please refer to the following graphic.
The following vector determines where the ball is at any time t:
R is equal to (x0 + v0 t, y0 + 1/2 g t2).
Where:
r is the ball's position vector at time t.
horizontal starting position is x0.
v0 is the starting horizontal speed.
t = time.
y0 is the starting position vertically.
g is the gravitational acceleration (-9.8 m/s2 if we consider the upward direction to be positive).
So that x0 and y0 are equal to 0, let's set the frame of reference origin to the throwing point.
The ball's position vector when it touches the ground is r1 (see figure). We can determine the location vector's vertical component using the equation whenever the ball touches the ground. The position's horizontal component is 30 metres and vertical component is -3.0 metres at that moment (see figure):
y = y0 + 1/2 · g · t² (y0 = 0)
y = 1/2 · g · t²
-3.0 m = 1/2 · (-9.8 m/s²) · t²
-3.0 m / -4.9 m/s² = t²
t = 0.78 s
Knowing that x = 30 m at this moment, we can now determine v0:
x = x0 + v0 · t (x0 = 0)
x = v0 · t
30 m = v0 · 0.78 s
v0 = 30 m / 0.78 s
v0 = 38 m/s
He pitches at a 38 m/s pace.
To learn more about pitches please click on below link
https://brainly.com/question/27128408
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