Question

exitance is defined as the power per unit area that is emitted from the surface of an object. for a blackbody radiator, the exitance emitted is dependent upon its temperature. calculate the exitance in w/cm2 for a blackbody radiator at 46 k and 335 k. exitance at 46 k

Answer 1

The exitance in W/cm² for a blackbody radiator at 335 K is 232 W/cm².

The exitance of a blackbody radiator is given by the Stefan-Boltzmann law: exitance = sigma × $T^4$

where exitance is the power per unit area emitted from the surface of the object, sigma is the Stefan-Boltzmann constant (5.67 x $10^{-8}$ W/m² K^4), and T is the temperature of the blackbody radiator in Kelvin.

To calculate the exitance in W/cm² for a blackbody radiator at 46 K, we can substitute this temperature into the equation:

exitance = 5.67 x $10^{-8}$ W/m² $K^4$ × $(46 K)^4$ = 0.000715 W/m²

Converting this to W/cm², we get:

exitance (W/cm²) = 0.000715 W/m² × (100 cm/m)² = 0.0715 W/cm²

To calculate the exitance in W/cm² for a blackbody radiator at 335 K, we can substitute this temperature into the equation:

exitance = 5.67 x $10^{-8}$ W/m² $K^4$ × $(335 K)^4$ = 2.32 W/m²

Converting this to W/cm², we get:

exitance (W/cm²) = 2.32 W/m² × (100 cm/m)² = 232 W/cm²

Learn more about the Stefan-Boltzmann Constant at

https://brainly.com/question/17204100?referrer=searchResults

#SPJ4