Question

Two identical small conducting spheres, having charges of opposite sign, attract each other with a force of 0.108N when separated by 0.5m. The spheres are connected by a conducting wire, which is then removed, and thereafter, they repel each other with a force of 0.036N. The initial charges of the spheres are :

Answer 1

The initial charges of the spheres are Q2=±1.0×10 ^−6C,Q1=∓3.0×10 ^−6 C.The answer to the query is provided below

A force operating on a body in the opposite direction of an accelerating force that is equal to the product of the accelerating force and the body's mass is known as initial force.

Let Q1 and Q2 represent the initial charge.

Initial force =F=K×Q1×Q2/r^2

                  =−0.108

F= 9×10 ^9×Q1×Q2/0.25

​    =−0.108

Q1⋅Q2=−3×10 ^−12

Since they are identical, they will have equal charges when connected.

Final charge = Q1+Q2/2

Final force =F=  9×10 ^9 ×(Q1+Q2)^ 2/4×0.25

                     =0.036

Q1+Q2=±2×10 ^−6

Q2=±1.0×10 ^−6C,Q1=∓3.0×10 ^−6 C

The initial charges of the spheres:Q2=±1.0×10 ^−6C , Q1=∓3.0×10 ^−6 C

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