Respuesta :
a liquid of density 1150 kg/m3 flows steadily through a pipe of varying diameter and height. at location 1, the flow speed is 9.21 m/s and the pipe diameter is 11.5 cm. at location 2, the pipe diameter is 15.5 cm. at location 1, the pipe is 9.15 m higher than it is at location 2. ignoring viscosity, dP = 114 kPa the difference in pressure between location 2 and location 1.
The difference between fluid pressure at location 2 and fluid pressure at location 1 is mathematically given as
dP = 114 kPa
Question Parameter(s):
Generally, the Bernoulli's equation is mathematically given as
P + ρ*g*y + v² =pipe constant
Where
A1*v1 = A2*v2
π*(0.105/2)²*9.91 = π*(0.167/2)²*v2
v2 = 3.9 m/s
Therefore
P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²
dP = 1290*9.8*9.01 + 9.91² - 3.9²
dP = 114 kPa
In conclusion, difference between fluid pressure is
dP = 114 kPa
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