Respuesta :
The magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is 0.203 Nm.
The net torque on a current-carrying loop in a magnetic field is given by the equation: Torque = (B × I × A × sin(theta))
where torque is the net torque on the loop, B is the magnitude of the magnetic field, I is the current in the wire, A is the area of the loop, and theta is the angle between the magnetic field and the normal to the loop.
In this case, the radius of the loop is 15 cm = 0.15 m, so the area of the loop is A = pi × r² = pi × (0.15 m)² = 0.07 m²
The current in the wire is 2.7 amps, and the magnitude of the magnetic field is 0.12 Tesla.
If the magnetic field is oriented parallel to the +x axis, the angle between the magnetic field and the normal to the loop is 0 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(0)) = 0 Nm
If the magnetic field is oriented to the +z axis, the angle between the magnetic field and the normal to the loop is 90 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(90)) = 0.252 Nm
If the magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(75)) = 0.203 Nm
Learn more about the torque at
https://brainly.com/question/18850713?referrer=searchResults
#SPJ4
