Question

14. An obstacle course was set up on a campus and 8 randomly selected volunteers were given the chance to compete while being timed. They took an energy drink and were given an opportunity to run the course again. From the given data, is there sufficient evidence at alpha =0.05 to conclude that the students did better the second time?

Answer 1

The data is not sufficient at alpha = 0.05 to infer that the pupils performed better the second time?

since t < critical value

Hence we fail to reject H₀.

Given data:

Before:

76,89,78,56,80,88,67

Sample N₁ = 8

Sum ∑x = 601

mean₁ = 75.125

S₁ = 10.54

after:

77,88,65,55,80,85,65

Sample N₂ = 7

mean₂ = 73.57

S₂ = 11.23

Hypothesis is given by:

H₀ : mean₁= mean₂

Hₐ : mean₁ > mean₂

given that

α = 0.05

df = 8+7-2

= 13

critical value = 1.771

t = 75.125-73.57/√(10.54)²/8 + (11.23)²/7

= 1.555/√13.88+18.01

= 1.555/5.64

t = 0.2757 since t < critical value

0.275 < 1.771

Here we fail to reject H₀

Learn more about Hypothesis here:

brainly.com/question/15980493

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