Question

The first three questions refer to the following information: Suppose a basketball team had a season of games with the following characteristics: 60% of all the games were at-home games. Denote this by H (the remaining were away games). 25% of all games were wins. Denote this by W (the remaining were losses). 20% of all games were at-home wins.
Of the at-home games, what proportion of games were wins? (Note: Some answers are rounded to two decimal places.)
.12
.15
.20
.33
.80
If the team won a game, how likely is it that this was a home game? (Note: Some answers are rounded to 2 decimal places.)
.05
.12
.15
.33
.80

Answer 1

i) Of the at-home games, proportion of games were wins in 0.33

ii) If the team won a game, proportion of home games 0.80

Proportion

• Proportion is an equation that defines that the two given ratios are equivalent to each other.
• For example, the time taken by train to cover 100km per hour is equal to the time taken by it to cover the distance of 500km for 5 hours

Given that,

P(H) = 60% = 0.60

P(W) = 25% = 0.25

P(H AND W) = 20% = 0.20

i) Of the at-home games, proportion of games were wins

= P(W | H)

= P (H AND W) / P(H)

= 0.20/0.60

= 0.33

Therefore, proportion of games were wins =0.33

ii)  If the team won a game, proportion of home games

= P (H| W)

= P (H AND W) / P(W)

= 0.20/0.25

= 0.80

Therefore, proportion of home games = 0.80

To learn more about proportion check the given link

https://brainly.com/question/19994681

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