Respuesta :
The force in member gj and gc of the truss, The members are in tension.
In ΔABH
tan 30° = BH/10
5.77 = BH
AH² = AB² + BH²
AH = 11.54ft
tanθ2 = 10/BH
tanθ2 = 10/5.77
θ2 = 60°
In ΔBCH
CH² = BC² + BH²
CH² = 133.33
CH = 11.54 ft
tanθ4 = BH/BC = 5.77/10 = 0.577
θ4 = 30°
θ3 + θ4 + 90 = 180°
θ3 = 60°
θ4 + θ1 = 90
30 + θ14 = 90
θ14 = 60
BH = DJ are same length
CI² = CD² + DJ²
= 10² + 5.77² = 133.33 = 11.54
tan θ6 = DJ/CD = 5.77/10 = 0.577
θ3 = 30°
θ6 = 60°
Similarly we get θ8 = 30° and θ7 = 60°
θ6 + θ7 + θ9 = 180°
θ9 = 60°
θ4 + θ10 + 60 + θ5 = 180°
θ10 = 60°
The members are in tension.
The force transferred through a rope, string, or wire when pushed by forces acting from opposite sides is referred to as tension. The tension force is applied along the entire length of the wire and exerts an equal amount of strain on the bodies at each end.
Every physical object that comes into contact with another one applies some sort of force. Depending on the type of item, these contact forces have different names. You can refer to a force as tension if a rope, cable, or chain is one of the objects it is pulling on.
Ropes and cables are useful for applying forces because they effectively transfer a force over a limited distance. Because ropes cannot effectively push, tension must be considered the pulling force.
Learn more about tension here:
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