The work required to pump the water out of the spout is 12,249.7 pi J.
Let's assume that the radius of the tank is 6 ft, the radius of the spout is 12 ft, and the height of the water in the tank is 16 ft.
To calculate the work required to pump the water out of the spout, we'll need to use the equation: W = (4/3)πr2(h+R-r) ρg where W is the work required, π is pi (3.1415), r is the radius of the tank, R is the radius of the spout, h is the height of the water in the tank, and ρg is the density of water (62.5 lb/ft3).
Plugging in our values, we get:
W = (4/3)π(6 ft)2(16 ft + 12 ft - 6 ft) (62.5 lb/ft3)
W = (4/3)π(36 ft2) (34 ft) (62.5 lb/ft3)
W = (4/3)π(2268 ft3) (62.5 lb/ft3)
W = 12,249.7 pi J
Therefore, the work required to pump the water out of the spout is 12,249.7 pi J.
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