Question

A car starts out at a speed of 50mph. A second car starts out 3 hours later at 65mph to overtake the first one. How many hours will the first car be on the road at the point where it is overtaken?
50 PTS! Please answer quick. you will get brainliest

Answer 1

To solve this problem, we can use the formula for average speed:

average speed = total distance traveled / time taken

We can set up the problem as follows:

50 mph = D / T

65 mph = (D+X) / (T+3)

Where D is the distance traveled by the first car, T is the time taken by the first car, and X is the distance between the two cars when the second car overtakes the first one.

We can then solve for T by substituting and rearranging the equations:

50 mph = D / T
D = 50 mph * T

65 mph = (D+X) / (T+3)
65 mph = (50 mph * T + X) / (T+3)
65 mph * (T+3) = 50 mph * T + X
195 mph * T + 195 = 50 mph * T + X
145 mph * T = X - 195
T = (X - 195) / 145 mph

We can then plug in the values for X and solve for T:

If the second car overtakes the first car after traveling 100 miles, then X = 100 miles.

T = (100 miles - 195) / 145 mph = -95/-145 mph = 0.657 hours

If the second car overtakes the first car after traveling 200 miles, then X = 200 miles.

T = (200 miles - 195) / 145 mph = 5/145 mph = 0.034 hours

So the first car will be on the road for approximately 0.657 hours or 0.034 hours, depending on the distance between the two cars when the second car overtakes the first one.



Please brainliest

Answer 2

Answer:

• 13 hours

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Both cars will make same distance but the first one will be on road for 3 more hours.

Let the number of hours the first car in travel be x.

Then set an equation:

• 50x = 65(x - 3)
• 50x = 65x - 195
• 65x - 50x = 195
• 15x = 195
• x = 13