Question

A rectangular solar panel has a length that is 11 inches shorter than 4 times it’s width. If the perimeter of the panel is 178 inches, what are the dimensions of the panel?

The width of the panel is *blank* inches.

Answer 1

Let w be the width of the panel.

The length of the panel is 4w-11 inches.

The perimeter of the panel is 2(w) + 2(4w-11) = 178 inches.

Combining like terms, we get 6w-22 = 178

Adding 22 to both sides, we get 6w = 200

Dividing both sides by 6, we get w = 33.333... inches.

The width of the panel is approximately 33.333 inches.

Answer 2

Answer:

• The width of the panel is 20 inches

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Let the width be x, then the length is 4x - 11.

The perimeter of the rectangle is:

• 2(x + 4x - 11) = 178

Solve it for x:

• 2(5x - 11) = 178
• 5x - 11 = 89
• 5x = 100
• x = 20