Question

cobalt (co) has an hcp crystal structure, an atomic radius of 0.1253 nm, and a c/a ratio of 1.623. compute the volume of the unit cell for co

Answer 1

cobalt (co) has an hcp crystal structure, an atomic radius of 0.1253 nm, and a c/a ratio of 1.623.  the volume of the unit cell for co is 1.126 * 10^-9 m^3

chemical compound with the atomic number 27 and the symbol Co.HCP is known as hexagonal close pack structure having unit cell closely packed in lattice.

For HCP, the  relation of edge length and radius can be shown as:

a = 2 r (2)^1/2

radius , r = 0.1253 nm = 0.1253 * 10^-9 m

Volume of HCP= a^3 = 16 R^3 (2)^1/2=

                         = 16 (0.1253 * 10^-9)^3 (2)^1/2

                         = 1.126 * 10^-9 m^3

Thus, volume of the unit cell is 1.126 * 10^-9 m^3

learn more about hexagonal close pack Refer: brainly.com/question/14956702

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