3.465 * 10^(-2) min^(-1) is the rate constant for this reaction. a certain first - order reaction has a half - life of 20.0 minutes
While Carbon-12 and Carbon-13, the other two naturally occurring carbon isotopes, have fairly stable half lives, Carbon-14 has a half life of 5,730 40 years. Therefore, if the number of C particles in the bucket is raised, the half-life of carbon-14 will also grow, making it more unstable. From this, we may infer that: If the number of C particles in the bucket is increased, the half-life of carbon-14 will also increase.
For the first order reaction
ln(Ao/At) = kt
At t=20 minutes, At=Ao/2, substituting these values we get
ln(Ao/(Ao/2)) = k * 20
k = ln2/20 = 3.465 * 10^(-2) min^(-1)
a certain first - order reaction has a half - life of 20.0 minutes. what is the rate constant for this reaction?
Learn more about half-life here:
https://brainly.com/question/24710827
#SPJ4
