An organic compound was analyzed and found to contain 70.6% carbon, 5.9% hydrogen, and 23.5% oxygen by mass. Additionally, the molar mass of the compound was experimentally determined to be 136 g/mole. What is the molecular formula for the compound?How many grams of MgCl2 would be required to prepare 250 mL of a 0.8 M solution of that solute in water? Please report your answer to two digits after the decimal place.

Respuesta :

This substance's chemical formula is C₈H₈O₂ and To create the 0.8 M solution, 19.04 g of  MgCl₂ must be dissolved in 250 mL of water.

How is a molecular formula composed?

The chemical formula for a chemical compound's molecular formula lists the variety of atoms that make up the molecule.

Briefing:

Assuming we have 100 g of the molecule, the masses of its constituent parts are as follows in order to get its molecular formula:

-70.6 g of carbon

-5.9 g of hydrogen

-23.5 g of oxygen

We next divide these masses by the molar masses of the constituent components to obtain the moles:

-carbon: 70.6 g / 12 g/mol = 5.88 mol

-hydrogen: 5.9 g / 1 g/mol = 5.9 mol

-oxygen: 23.5 g / 16 g/mol = 1.47 mol

To get the molar ratio, divide the moles by the least number (1.47 mol for oxygen):

-carbon: 5.88 mol / 1.47 mol = 4

-hydrogen: 5.9 mol / 1.47 mol = 4

-oxygen: 1.47 mol / 1.47 mol = 1

As a result, we have the empirical formula:

This empirical formula's molar mass is

4 x 12 g/mol + 4 x 1 g/mol + 16 g/mol = 68 g/mol

In order to arrive at our final result, we divide the molar mass of our compound by the molar mass of the empirical formula.

136 g/mol / 68 g/mol = 2

We multiply the index numbers by 2 to get the molecular formula C₈H₈O₂.

The following equation is used to determine how much MgCl2 is required to make a 0.8 M solution of it in 250 mL (0.250 L):

c = n/V ⇒ n = c * V

c - molarity of the solution (0.8 M)

n - number of moles of solute

V - the volume of the solution

Now we plug in the values we have:

n = 0.8 M * 0.250 L

n = 0.2 mol

Now, we can determine the mass of the solute using the molar mass of MgCl2 (M = 95.211 g/mol):

n = m/M

m = n * M

m - the mass of the substance

m = 0.2 mol * 95.211 g/mol

m = 19.04 g

Therefore, 19.04 g of MgCl2 are required to create a 0.8 M solution in 250 mL.

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