Question

a satellite moves in a circular orbit at a constant speed v0v0 around earth at a distance rr from its center. the force exerted on the satellite is f0f0. an identical satellite orbits earth at a distance of 3r3r from the center of the earth. how does the tangential speed, vtvt, of the satellite at distance 3r3r compare to the speed v0v0 of the satellite at rr?

Answer 1

Tangential speed vT, for the satellite that orbits the earth from a distance 3R is : vT= v0/3.

What is tangential speed?

Linear component of the speed along any point of the circle involved in the circular motion is called tangential speed.

Given;

Vo is Speed ; R is the distance of center of the earth

Fo is the force exerted on satellite

Let vT be tangential speed

For the satellite, gravitational force (Fg)is equal to centripetal force(Fc),

Hence, Fg = Fc = Fo

GMm/R² = mvo/3R²

Thus, GM = (v0)²R

As given, R = 3R

So, GMm/3R² = m(v0)²/3R

GMm/3R² = m(vT)²/3R

So, GM= 9R * (vT)²

Now, (v0)²R = 9(vT)²R

(vT)²= (v0)²/9

So, vT= v0/3

Therefore, the tangential speed, vT, for the satellite that orbits the earth from distance 3R is v0/3.

To know more about tangential speed, refer

https://brainly.com/question/4387692

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