A giant ocean tank at an aquarium has acrylic plastic walls 18cm thick. The index of refraction of
acrylic plastic is 1.49. A fish is 220cm from the inside wall. To a viewer on the outside, how far
does the fish appear to be from the outside wall? (Hint: The image of the first refraction is the
object for the second refraction

Respuesta :

To a viewer on the outside, the fish appear to be 213.7 cm from the outside wall, according to the refraction.

The fish appears to be 213.7 cm from the outside wall. This is calculated using the formula: 1/di + 1/do = 1/f, where di is the distance of the object from the inside wall, do is the distance of the object from the outside wall, and f is the focal length of the lens. In this case, di = 220 cm, f = (1.49)(18 cm), and do = 1/((1/220)+(1/f)) = 213.7 cm. The image of the fish is formed when light passes through the acrylic plastic wall. Upon entering the wall, the light’s speed decreases, causing it to bend towards the normal. This bending is known as refraction. As the light passes through the wall, a second refraction occurs, this time towards the wall. This second refraction gives the viewer on the outside an image of the fish which appears to be 213.7 cm from the outside wall.

To know more about  refraction refer to the link  brainly.com/question/14760207

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