The work done lifting the bucket to the top of the building 3454.5 joules.
F = ma
a = 9.8 m/sec²
F(x) = ( 25 - 0.2x) 9.8
F(x) = 245 - 1.96x, 0 < x< 15
Work done w = [tex]\left \{ {{y=15} \atop {x=0}} \right. F(x) dx[/tex]
W = 245x - 0.98x²]0 to 15
= 245 (15) - 0.98(15)²
= 3675 - 220.5 = 3454.5 joules
A body experiences some acceleration or, moreover, its speed rises or declines depending on the direction of the force when we apply a thrust to a block with force "F." The kinetic energy of the system changes as speed increases or decreases. Energy must be transformed into another form as it cannot be created or destroyed, as far as we are aware. This view refers to it as completed job. When negative work is finished, energy levels drop, and when positive work is finished, energy levels rise. Now that the concept of measuring work is clear, we can proceed.
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