Question

the joint is subjected to the force system shown. determine the state of stress at points a and b, and sketch the results on differential elements located at these points. the member has a rectangular cross-sectional area of width 0.5 in. and thickness 1 in.

Answer 1

The state of stress at points a and b is 800 psi and -19632.7Psi.

Normal Stress at point A = N/A + My/I

Ya = 0

Normal Stress at point A = 400/0.5  = 800 psi

At point B

Normal stress = N/A - MYb/I = 400/0.5 - 1700 × 1/2 / 0.0416 = -19632.7Psi

When you tighten a screw or twist a metal bar along its longitudinal axis, you cause shear stress in the solid. Shear stress in fluids is caused by processes like the movement of gases and liquids through pipes, the gliding of a metal surface over a liquid lubricant, and the flight of an airplane through the atmosphere. Layers of the fluid travel over each other at varying speeds like individual cards in a spread deck of cards when shear loads, no matter how minor, are applied to real fluids. This results in continual deformation or flow. Shear stress is often referred to as shear modulus.

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