The formula for efficiency of an original carnot engine is;
e = 1 - T(C) /T(H) ——— eq 1
The efficiency is;
e(12) = (W1 + W2)/Q(H1)
Where W1 is work done by 1st engine; W2 is work done by second engine and Q(H1) is the heat input to the first engine.
W = Q(H) + Q(C)
e(12) = [Q(H1) + Q(C1) + Q(H2) + Q(C2)] / Q(H1)
e(12) equation compared to this, QH2 = -QC1
e(12) = [Q(H1) + Q(C1) - Q(C1) + Q(C2)] / Q(H1)
So e(12) = [Q(H1) + Q(C2)] / Q(H1)
So e(12) = 1 + [Q(C2)/Q(H1)] ———eq 2
Also,
Q(C2) /Q(H2) = (-Tc/T')
Q(C2) = -Q(H2) (Tc/T')
This is also equal to Q(C1) (TC/T')
But Q(C1) is also equal to;
-Q(H1) (T'/TH)
Q(C2) = -Q(H1) (T'/TH)(TC/T')
Q(C2) = -Q(H1)(TC/TH)
Replacing this with Q(C2) in eq 2 to obtain;
e(12) = 1 + [[-Q(H1)(TC/TH)] /Q(H1)]
e(12) = 1 - TC/TH
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