When calculating the amount of energy needed to raise a 10 g block of ice from -20 to -2, the latent heat of fusion for ice is 80 cal/g, and there are 7250 canneries.
Consequently, 5460 J of heat are needed. Therefore, 10 grammes of ice will take 10X384 = 3840 Joules of energy, which equates to 917 calories. You will need 10 X 20 calories to raise the temperature of the water from 0° to 20°.For example, water has a specific heat capacity of 4.187 kJ/kgK, ice has a specific heat capacity of 2.108 kJ/kgK, and water vapour (steam) has a specific heat capacity of 1.996 kJ/kgK.
The heat of fusion is the amount of heat required to turn 1 g of solid into a liquid without causing a change in temperature (Weast, 1964, p. F-44).It is also referred to as the "latent heat of fusion" and is a latent heat. Ice fuses with a molar heat of 6.01 kJ/mol.
To learn more about fusion energy refer to :
https://brainly.com/question/27838263
#SPJ4
