Question

estimate the radiation pressure due to a 100- w bulb at a distance of 5.0 cm from the center of the bulb. assume that light is complitely absorbed.

Answer 1

The radiation pressure due to 100w bulb at a distance of 5.0cm from the center of the bulb is  $1.06*10^{-5} N/m^{2}$

Radiation pressure is the mechanical pressure exerted on any surface due to momentum exchange between an object and an electromagnetic field. It includes pulses of light or electromagnetic radiation of any wavelength that are absorbed, reflected, or emitted by matter of any size.

Calculation :

power out put of the bulb p' = 100 W

distance of the finger from the bulb  $r = 5.0*10^{-2}$

the radiation pressure is P = I/c   ............. (1)

but intensity I = p'/A

so , eq (1) becomes

P = p'/Ac    .................. (2)

here, speed of light  $c = 3*10^{8}$

                     area $A = 4\pi r^{2}$

                                 $= (4)*(3.14)*(5.0*10^{-2}m )^{2}$

                                $= 314*10^{-4}$$m^{2}$

substitute the given data in eq (2) , we get

radiation pressure P = p'/Ac  

                                    $= (100 W)/(314*10^{-4}m^{2} )(3*10^{8}m/s )$

                                    $= 1.06*10^{-5} N/m^{2}$

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