A 4-person grievance committee is to be selected out of 2 how many ways can the following committees be selected? Complete parts (A) through (E) below. (A) 3 from A and 1 from B A and B, with 11 and 30 people, respectively. in (B) 2 from A and 2 from B (C) All from A (D)4 people regardless of department (E) At least 3 from department A

Respuesta :

According to the combination technique,

A) 3 from A and 1 from B = 16320

B) 2 from A and 2 from B = 29070

C) All from A = 3060

D) 4 people regardless of department = 73815

E) at least 3 from department A = 19380

In math combination technique is used to determines the number of possible arrangements in a collection of items where the order of the selection does not matter.

Here we have given that 4-person grievance committee is to be selected out of 2 how many ways can the following committees be selected

And we need to find the following

Here we know that  4-person grievance committee is to be selected out of 2 departments, A and B, with 18 and 20 people.

In this one we have to find the number ways can the following committees be selected.

A) While the first condition is to 3 from A and 1 from B

Here the term "and" means to multiply

Then it can be written as

=> (18 people choose 3) x (20 people choose 1)

=> (18C3)(20C1) = (816)(20) = 16320

B) And then the next condition is 2 from A and 2 from B

In this one is written as,

=> (18 people choose 2) x (20 people choose 2)

=> (18C2)(20C2) = (153)(190) = 29070

C) All from A

which is equal to the following,

=> 18 people choose 4 = 18C4 = 3060

D) Next, we have to do the calculation for 4 people regardless of department

=> 18+20 or 38 people choose 4 = 38C4 = 73815

E) Finally, at least 3 from department A.

'In other words, it can be written as choose 3 from department A and choose 1 from department B or  Choose 4 all from department A

Where "And" means to multiply and "or" means to add.

Therefore, the condition is written as,

=> [(18 people choose 3) times (20 people choose 1)] plus  (18 people choose 4)

=> (18C3)(20C1) + (18C4) = (816)(20) + 3060 = 19380

To know more about Combination technique here.

https://brainly.com/question/28998705

#SPJ4

ACCESS MORE