Question

Which of the following gives the correct matrix for this system of equations in reduced row echelon form? x1-3x2-x3 + 3x4 = 2 -xi-2x2-x3 +4x4 = 2 -2x1+4x2 +4x3 +4x4 =-3 12 5 14 100 17 5 18 001 14 1 -3 -1 32 0 -5 -2 74 00ー36-3 b) 1 0 0 -36 9 1 22 010 001_ -_ 1 22 -1 -3 1 3 2 d 0 1 0 0 0 22 -12 -7 1 0 0 0 e) 25 010 -5 0 0 6 -16 f O None of the above

Answer 1

The correct matrix for this system of equations in row reduced echelon form amongst the given options is none of the above.

The given system of equations to get the reduced row echelon form is:

x1 - 3x2 - x3 +3x4 = 2

-x1 - 2x2 - x3 +4x4 = 2

-2x1 + 4x2 + 4x3 +4x4 = -3

To get the reduced row echelon form we need to form the matrix:

$\left[\begin{array}{ccccc}1&-3&-1&3&2\\-1&-2&-1&4&2\\-2&4&4&4&-3\end{array}\right]$

Row reduced echelon form of a matrix is one in which the pivot points equal 1, go from top left to bottom right, there are 0's above and below each pivot point.

R2-R1:

$\left[\begin{array}{ccccc}1&-3&-1&3&2\\-2&1&0&1&0\\-2&4&4&4&-3\end{array}\right]$

R3-R2 then R2+2R1 then R1+R3 then R2+2R3 then R3-3R2

$\left[\begin{array}{ccccc}1&0&3&6&-1\\0&1&6&13&-2\\0&0&-14&-36&3\\\end{array}\right]$

(-1/14)R3 then R2-6R3 then R1-3R3

$\left[\begin{array}{ccccc}1&0&0&-12/7&-5/14\\0&1&0&-17/7&-5/7\\0&0&1&18/7&-3/14\\\end{array}\right]$

which is the reduced row echelon form of the given system of equations.

To know more about the reduced row echelon form:

https://brainly.com/question/13263007

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