Question

arun is older than suav. their ages are consecutive integers. find arun's age if the sum of the square of arun's age and 4 times suav's age is 92.

Answer 1

If the ages of Arun and Suav are consecutive integers than the Arun's age is 8 years .

In the question ,

it is given that ,

Arun is older than Suav ,

and their ages are consecutive integers ,

Let the Suav's age be = "x"

So ,  the Arun's age be = "x+1" .

it is given that , the sum of the square of Arun's age and 4 times Suav's age is 92.

that means ;

(x+1)² +4x = 92

x² +6x + 1 = 92

x² + 6x - 91 = 0

Solving the quadratic equations ,

we get ,

x = 7 and x = -13 .

age cannot be negative , So ,

x = 7 ,

thus, the Arun's age will be = 7 + 1 = 8 years.

Therefore , the age of Arun is 8 years .

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